WebSep 22, 2024 · Initially i = 0. Since case 0 is true i becomes 5, and since there is no break statement till last statement of switch block, i becomes 16. Now in next iteration no case is true, so execution goes to default and i becomes 21. WebSystem.out.println ("The value of sum. is " + sum); a) The value of sum is 65. b) The value of sum is 66. c) The value of sum is 55. d) The value of sum is 56. b) The value of sum is 66. 11) What is the output of the following code snippet? int i = 1;
以下代码片段执行结束后,变量i的值是多少? int i = 1; do { i += 5; } …
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What will be the output of the program? int i = 1, j = 10; do
WebView the full answer. Transcribed image text: int i=1; while (i <= 10) System.out.println "X"; i = i +3; 5 marks 2. Using your knowledge in looping algorithm deduce an algorithm that can sort the following numbers in a 1 dimensional array in ascending order. Write the equivalent Java Program for the algorithm you generated 5 marks 3 10 24 4 9 7 3. WebCorrect Answer: i = 0. Explanation: Math.random () returns a double value greater than or equal to 0 and less than 1. Its value is stored to an int but as this is a narrowing conversion, a cast is needed to tell the compiler that you are aware that there may be a loss of precision. WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer. Question: Hand Tracing Table 1. Hand-trace the following code, showing the value of n and the output. int n = 5; while (n >= 0) { n--; print n; } Hand Tracing Table Goes Here: 2. Hand-trace the following code ... feather disposable scalpel pzn